#18199: "Swiss tournament pairing improvement: color selection (hive, chess)"
무슨 일이 발생했나요? 아래에서 선택하세요
무슨 일이 발생했나요? 아래에서 선택하세요
같은 내용에 대하여 이미 등록된 보고가 있는지 확인해주세요
그렇다면, 이 보고를 추천해주세요. 추천을 가장 많이 받은 보고부터 우선적으로 처리됩니다!
# | Status | Votes | Game | Type | Title | Last update |
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상세한 설명
• 만약 오류 메세지가 화면에 나타났다면, 그 오류 메세지를 복사해서 붙여넣어 주시기 바랍니다.
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• 무엇을 하고 싶었고, 무엇을 했고, 무슨 일이 일어났는지를 설명해 주십시오
• 브라우저가 무엇입니까?
Google Chrome v81
• 현재 설정된 언어가 아니라 영어로 표시되는 문장을 복사 후 붙여넣어 주세요. 만약에 버그에 대한 스크린샷을 가지고 계신다면 Imgur.com 사이트에 업로드 하시고, 여기에 링크를 복사/붙여넣기 하시기 바랍니다.
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• 해당 문장이 번역 본부에서 표시됩니까? 만약 그렇다면, 번역된 지 24시간이 경과했습니까?
• 브라우저가 무엇입니까?
Google Chrome v81
• 최대한 쉽게 그 뜻을 이해할 수 있도록 당신의 제안을 정확하고 명료하게 설명해 주십시오.
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• 브라우저가 무엇입니까?
Google Chrome v81
• 당신이 막혔을 때 화면에 무엇이 나타났습니까?(검은 화면? 게임 인터페이스? 오류 메시지?)
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• 브라우저가 무엇입니까?
Google Chrome v81
• 어느 규칙이 BGA 서비스에서 존중되지 않았습니까?
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• 게임 리플레이에서 룰 위반을 확인할 수 있습니까?만약 그렇다면, 몇번째 수에서 룰 위반이 있나요?
• 브라우저가 무엇입니까?
Google Chrome v81
• 당신이 하고 싶었던 게임 내 행동이 어느 것입니까?
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• 이 게임 행동을 하기 위해 무엇을 시도했습니까?
• 당신이 이것을 하려고 했을 때 무슨 일이 일어났습니까?(오류 메시지, 게임 상태창 메시지 등)
• 브라우저가 무엇입니까?
Google Chrome v81
• 어떤 부분에서 문제가 발생 하였나요(문제가 발생했을 당시 어떤 지시가 내려졌었나요)?
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• 당신이 게임 행동을 하려 했을 때 무슨 일이 일어났습니까?(오류 메시지, 게임 상태 막대 메시지, ...)
• 브라우저가 무엇입니까?
Google Chrome v81
• 디스플레이 문제를 설명해주세요. 만약에 버그에 대한 스크린샷을 가지고 계신다면 Imgur.com 사이트에 업로드 하시고, 여기에 링크를 복사/붙여넣기 하시기 바랍니다.
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• 브라우저가 무엇입니까?
Google Chrome v81
• 현재 설정된 언어가 아니라 영어로 표시되는 문장을 복사 후 붙여넣어 주세요. 만약에 버그에 대한 스크린샷을 가지고 계신다면 Imgur.com 사이트에 업로드 하시고, 여기에 링크를 복사/붙여넣기 하시기 바랍니다.
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• 해당 문장이 번역 본부에서 표시됩니까? 만약 그렇다면, 번역된 지 24시간이 경과했습니까?
• 브라우저가 무엇입니까?
Google Chrome v81
• 최대한 쉽게 그 뜻을 이해할 수 있도록 당신의 제안을 정확하고 명료하게 설명해 주십시오.
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• 브라우저가 무엇입니까?
Google Chrome v81
보고 이력
boardgamearena.com/tournament?id=38119
For example, in this tournament Frasco has all 4 games as white and pcapella has all 4 games black boardgamearena.com/tournament?id=106569
boardgamearena.com/bug?id=32483
boardgamearena.com/bug?id=32713
boardgamearena.com/bug?id=72619
리포트에 내용 추가하기
- 다른 테이블 번호 / 수 번호
- 새로고침을 해서 문제가 해결 되었습니까?
- 문제가 얼마나 자주 일어났습니까?
- 만약에 버그에 대한 스크린샷을 가지고 계신다면 Imgur.com 사이트에 업로드 하시고, 여기에 링크를 복사/붙여넣기 하시기 바랍니다.